4x^2+24x-20=8

Solution for 4x^2+24x-20=8 equation:

4x^2+24x-20=8

We move all terms to the left:

4x^2+24x-20-(8)=0

We add all the numbers together, and all the variables

4x^2+24x-28=0

a = 4; b = 24; c = -28;
Δ = b2-4ac
Δ = 242-4·4·(-28)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-32}{2*4}=\frac{-56}{8}
=-7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+32}{2*4}=\frac{8}{8}
=1
$